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4x^2-18x-112=0
a = 4; b = -18; c = -112;
Δ = b2-4ac
Δ = -182-4·4·(-112)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-46}{2*4}=\frac{-28}{8} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+46}{2*4}=\frac{64}{8} =8 $
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